m-8/m+15=0.5

Solution for m-8/m+15=0.5 equation:

m-8/m+15=0.5

We move all terms to the left:

m-8/m+15-(0.5)=0


Domain of the equation: m!=0

m∈R


We add all the numbers together, and all the variables

m-8/m+14.5=0

We multiply all the terms by the denominator


m*m+(14.5)*m-8=0

We multiply parentheses

m*m+14.5m-8=0

Wy multiply elements

m^2+14.5m-8=0

a = 1; b = 14.5; c = -8;
Δ = b2-4ac
Δ = 14.52-4·1·(-8)
Δ = 242.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14.5)-\sqrt{242.25}}{2*1}=\frac{-14.5-\sqrt{242.25}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14.5)+\sqrt{242.25}}{2*1}=\frac{-14.5+\sqrt{242.25}}{2}
$