m-9=(2m-12)/3

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Solution for m-9=(2m-12)/3 equation: 



m-9=(2m-12)/3

We move all terms to the left:

m-9-((2m-12)/3)=0

We multiply all the terms by the denominator


m*3)-((2m-12)-9*3)=0

We add all the numbers together, and all the variables

m*3)-((2m-12)=0

Wy multiply elements

3m^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{6}=0$

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