m/2*(m+1)=m/2*(m+1)

Solution for m/2*(m+1)=m/2*(m+1) equation:

m/2(m+1)=m/2(m+1)

We move all terms to the left:

m/2(m+1)-(m/2(m+1))=0


Domain of the equation: 2(m+1)!=0

m∈R



Domain of the equation: 2(m+1))!=0

m∈R


We calculate fractions


(-2m^2m/(2(m+1)*2(m+1)))+(2m^2m/(2(m+1)*2(m+1)))=0


We calculate terms in parentheses: +(-2m^2m/(2(m+1)*2(m+1))), so:

-2m^2m/(2(m+1)*2(m+1))

We multiply all the terms by the denominator


-2m^2m

Back to the equation:

+(-2m^2m)



We calculate terms in parentheses: +(2m^2m/(2(m+1)*2(m+1))), so:

2m^2m/(2(m+1)*2(m+1))

We multiply all the terms by the denominator


2m^2m

Back to the equation:

+(2m^2m)


We get rid of parentheses

-2m^2m+2m^2m=0