m/5+3(M-1)/2=2M-6

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Solution for m/5+3(M-1)/2=2M-6 equation: 


x in (-oo:+oo)

(3*(M-1))/2+m/5 = 2*M-6 // - 2*M-6

(3*(M-1))/2-(2*M)+m/5+6 = 0

(3*(M-1))/2-2*M+m/5+6 = 0

(3*5*(M-1))/(2*5)+(-2*2*5*M)/(2*5)+(2*m)/(2*5)+(2*5*6)/(2*5) = 0

3*5*(M-1)-2*2*5*M+2*m+2*5*6 = 0

2*m-5*M-15+60 = 0

2*m-5*M+45 = 0

(2*m-5*M+45)/(2*5) = 0

(2*m-5*M+45)/(2*5) = 0 // * 2*5

2*m-5*M+45 = 0

x belongs to the empty set

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