m/8m+2=16m

Solution for m/8m+2=16m equation:

m/8m+2=16m

We move all terms to the left:

m/8m+2-(16m)=0


Domain of the equation: 8m!=0

m!=0/8

m!=0

m∈R


We add all the numbers together, and all the variables

-16m+m/8m+2=0

We multiply all the terms by the denominator


-16m*8m+m+2*8m=0

We add all the numbers together, and all the variables

m-16m*8m+2*8m=0

Wy multiply elements

-128m^2+m+16m=0

We add all the numbers together, and all the variables

-128m^2+17m=0

a = -128; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-128)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-128}=\frac{-34}{-256}
=17/128
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-128}=\frac{0}{-256}
=0
$