m1/8(3m-2)=1/4(m+5)

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Solution for m1/8(3m-2)=1/4(m+5) equation: 



m1/8(3m-2)=1/4(m+5)

We move all terms to the left:

m1/8(3m-2)-(1/4(m+5))=0



Domain of the equation: 8(3m-2)!=0

m∈R





Domain of the equation: 4(m+5))!=0

m∈R



We calculate fractions


(4m^2m/(8(3m-2)*4(m+5)))+(-8m3/(8(3m-2)*4(m+5)))=0



We calculate terms in parentheses: +(4m^2m/(8(3m-2)*4(m+5))), so:

4m^2m/(8(3m-2)*4(m+5))

We multiply all the terms by the denominator


4m^2m

Back to the equation:

+(4m^2m)





We calculate terms in parentheses: +(-8m3/(8(3m-2)*4(m+5))), so:

-8m3/(8(3m-2)*4(m+5))

We multiply all the terms by the denominator


-8m3

We add all the numbers together, and all the variables

-8m^3

We do not support empression: m^3

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