m1=25,m2=25

Solution for m1=25,m2=25 equation:

m1=25.m^2=25

We move all terms to the left:

m1-(25.m^2)=0

We add all the numbers together, and all the variables

m-(25.m^2)=0

We get rid of parentheses

-25.m^2+m=0

We add all the numbers together, and all the variables

-25m^2+m=0

a = -25; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-25)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-25}=\frac{-2}{-50}
=1/25
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-25}=\frac{0}{-50}
=0
$