m1=88m2=27m3=

Solution for m1=88m2=27m3= equation:

m1=88m^2=27m^3=

We move all terms to the left:

m1-(88m^2)=0

determiningTheFunctionDomain
-88m^2+m1=0

We add all the numbers together, and all the variables

-88m^2+m=0

a = -88; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-88)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-88}=\frac{-2}{-176}
=1/88
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-88}=\frac{0}{-176}
=0
$