m2+2m-48=-6

Solution for m2+2m-48=-6 equation:

m2+2m-48=-6

We move all terms to the left:

m2+2m-48-(-6)=0

We add all the numbers together, and all the variables

m^2+2m-42=0

a = 1; b = 2; c = -42;
Δ = b2-4ac
Δ = 22-4·1·(-42)
Δ = 172
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{172}=\sqrt{4*43}=\sqrt{4}*\sqrt{43}=2\sqrt{43}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{43}}{2*1}=\frac{-2-2\sqrt{43}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{43}}{2*1}=\frac{-2+2\sqrt{43}}{2}
$