m2+5-m=65

Solution for m2+5-m=65 equation:

m2+5-m=65

We move all terms to the left:

m2+5-m-(65)=0

We add all the numbers together, and all the variables

m^2-1m-60=0

a = 1; b = -1; c = -60;
Δ = b2-4ac
Δ = -12-4·1·(-60)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{241}}{2*1}=\frac{1-\sqrt{241}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{241}}{2*1}=\frac{1+\sqrt{241}}{2}
$