m2+6m-82=0

Solution for m2+6m-82=0 equation:

m2+6m-82=0

We add all the numbers together, and all the variables

m^2+6m-82=0

a = 1; b = 6; c = -82;
Δ = b2-4ac
Δ = 62-4·1·(-82)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{91}}{2*1}=\frac{-6-2\sqrt{91}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{91}}{2*1}=\frac{-6+2\sqrt{91}}{2}
$