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m2+7m-294=4
We move all terms to the left:
m2+7m-294-(4)=0
We add all the numbers together, and all the variables
m^2+7m-298=0
a = 1; b = 7; c = -298;
Δ = b2-4ac
Δ = 72-4·1·(-298)
Δ = 1241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{1241}}{2*1}=\frac{-7-\sqrt{1241}}{2} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{1241}}{2*1}=\frac{-7+\sqrt{1241}}{2} $
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