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m2+8m+16=0
We add all the numbers together, and all the variables
m^2+8m+16=0
a = 1; b = 8; c = +16;
Δ = b2-4ac
Δ = 82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{-8}{2}=-4$
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