m2-14m+15=-18

Solution for m2-14m+15=-18 equation:

m2-14m+15=-18

We move all terms to the left:

m2-14m+15-(-18)=0

We add all the numbers together, and all the variables

m^2-14m+33=0

a = 1; b = -14; c = +33;
Δ = b2-4ac
Δ = -142-4·1·33
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-8}{2*1}=\frac{6}{2}
=3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+8}{2*1}=\frac{22}{2}
=11
$