m2-8m-10008=0

Solution for m2-8m-10008=0 equation:

m2-8m-10008=0

We add all the numbers together, and all the variables

m^2-8m-10008=0

a = 1; b = -8; c = -10008;
Δ = b2-4ac
Δ = -82-4·1·(-10008)
Δ = 40096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{40096}=\sqrt{16*2506}=\sqrt{16}*\sqrt{2506}=4\sqrt{2506}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{2506}}{2*1}=\frac{8-4\sqrt{2506}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{2506}}{2*1}=\frac{8+4\sqrt{2506}}{2}
$