m2-9m=8

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Solution for m2-9m=8 equation:



m2-9m=8
We move all terms to the left:
m2-9m-(8)=0
We add all the numbers together, and all the variables
m^2-9m-8=0
a = 1; b = -9; c = -8;
Δ = b2-4ac
Δ = -92-4·1·(-8)
Δ = 113
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{113}}{2*1}=\frac{9-\sqrt{113}}{2} $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{113}}{2*1}=\frac{9+\sqrt{113}}{2} $

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