m2=1.14

Solution for m2=1.14 equation:

m2=1.14

We move all terms to the left:

m2-(1.14)=0

We add all the numbers together, and all the variables

m^2-1.14=0

a = 1; b = 0; c = -1.14;
Δ = b2-4ac
Δ = 02-4·1·(-1.14)
Δ = 4.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.56}}{2*1}=\frac{0-\sqrt{4.56}}{2}
=-\frac{\sqrt{}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.56}}{2*1}=\frac{0+\sqrt{4.56}}{2}
=\frac{\sqrt{}}{2}
$