m2=112+X

Solution for m2=112+X equation:

m2=112+m

We move all terms to the left:

m2-(112+m)=0

We add all the numbers together, and all the variables

m2-(m+112)=0

We add all the numbers together, and all the variables

m^2-(m+112)=0

We get rid of parentheses

m^2-m-112=0

We add all the numbers together, and all the variables

m^2-1m-112=0

a = 1; b = -1; c = -112;
Δ = b2-4ac
Δ = -12-4·1·(-112)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{449}}{2*1}=\frac{1-\sqrt{449}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{449}}{2*1}=\frac{1+\sqrt{449}}{2}
$