m2=300+20m

Solution for m2=300+20m equation:

m2=300+20m

We move all terms to the left:

m2-(300+20m)=0

We add all the numbers together, and all the variables

m2-(20m+300)=0

We add all the numbers together, and all the variables

m^2-(20m+300)=0

We get rid of parentheses

m^2-20m-300=0

a = 1; b = -20; c = -300;
Δ = b2-4ac
Δ = -202-4·1·(-300)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-40}{2*1}=\frac{-20}{2}
=-10
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+40}{2*1}=\frac{60}{2}
=30
$