m2=5m+24m2=5m+24

Solution for m2=5m+24m2=5m+24 equation:

m2=5m+24m^2=5m+24

We move all terms to the left:

m2-(5m+24m^2)=0

We add all the numbers together, and all the variables

m^2-(5m+24m^2)=0

We get rid of parentheses

m^2-24m^2-5m=0

We add all the numbers together, and all the variables

-23m^2-5m=0

a = -23; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-23)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-23}=\frac{0}{-46}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-23}=\frac{10}{-46}
=-5/23
$