m=-(4+m)+12

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Solution for m=-(4+m)+12 equation: 



m=-(4+m)+12

We move all terms to the left:

m-(-(4+m)+12)=0

We add all the numbers together, and all the variables

m-(-(m+4)+12)=0



We calculate terms in parentheses: -(-(m+4)+12), so:

-(m+4)+12

We get rid of parentheses

-m-4+12

We add all the numbers together, and all the variables

-1m+8

Back to the equation:

-(-1m+8)



We get rid of parentheses

m+1m-8=0

We add all the numbers together, and all the variables

2m-8=0

We move all terms containing m to the left, all other terms to the right

2m=8

m=8/2

m=4

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