m=-(4+m)-2

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Solution for m=-(4+m)-2 equation: 



m=-(4+m)-2

We move all terms to the left:

m-(-(4+m)-2)=0

We add all the numbers together, and all the variables

m-(-(m+4)-2)=0



We calculate terms in parentheses: -(-(m+4)-2), so:

-(m+4)-2

We get rid of parentheses

-m-4-2

We add all the numbers together, and all the variables

-1m-6

Back to the equation:

-(-1m-6)



We get rid of parentheses

m+1m+6=0

We add all the numbers together, and all the variables

2m+6=0

We move all terms containing m to the left, all other terms to the right

2m=-6

m=-6/2

m=-3

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