m=2;16/2m=

Solution for m=2;16/2m= equation:

m=216/2m=

We move all terms to the left:

m-(216/2m)=0


Domain of the equation: 2m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

m-(+216/2m)=0

We get rid of parentheses

m-216/2m=0

We multiply all the terms by the denominator


m*2m-216=0

Wy multiply elements

2m^2-216=0

a = 2; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·2·(-216)
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*2}=\frac{0-24\sqrt{3}}{4}
=-\frac{24\sqrt{3}}{4}
=-6\sqrt{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*2}=\frac{0+24\sqrt{3}}{4}
=\frac{24\sqrt{3}}{4}
=6\sqrt{3}
$