m=2;16/m

Solution for m=2;16/m equation:

m=216/m

We move all terms to the left:

m-(216/m)=0


Domain of the equation: m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

m-(+216/m)=0

We get rid of parentheses

m-216/m=0

We multiply all the terms by the denominator


m*m-216=0

Wy multiply elements

m^2-216=0

a = 1; b = 0; c = -216;
Δ = b2-4ac
Δ = 02-4·1·(-216)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*1}=\frac{0-12\sqrt{6}}{2}
=-\frac{12\sqrt{6}}{2}
=-6\sqrt{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*1}=\frac{0+12\sqrt{6}}{2}
=\frac{12\sqrt{6}}{2}
=6\sqrt{6}
$