m=3(u+1)/7-2(u-2)/21-(2-u)/3

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Solution for m=3(u+1)/7-2(u-2)/21-(2-u)/3 equation:


x in (-oo:+oo)

m = (3*(u+1))/7-((2*(u-2))/21)-((2-u)/3) // - (3*(u+1))/7-((2*(u-2))/21)-((2-u)/3)

(2*(u-2))/21-((3*(u+1))/7)+(2-u)/3+m = 0

(-3/7)*(u+1)+(2*(u-2))/21+(2-u)/3+m = 0

(2*(u-2))/21-3/7*(u+1)+(2-u)/3+m = 0

(-3/7*3*21*(u+1))/(3*21)+(2*3*(u-2))/(3*21)+(21*(2-u))/(3*21)+(3*21*m)/(3*21) = 0

2*3*(u-2)-3/7*3*21*(u+1)+21*(2-u)+3*21*m = 0

63*m-21*u-21*u-39+42 = 0

63*m-42*u+3 = 0

(63*m-42*u+3)/(3*21) = 0

(63*m-42*u+3)/(3*21) = 0 // * 3*21

63*m-42*u+3 = 0

x belongs to the empty set

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