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m=4(m-2)(m+2)
We move all terms to the left:
m-(4(m-2)(m+2))=0
We use the square of the difference formula
m^2+m+4=0
a = 1; b = 1; c = +4;
Δ = b2-4ac
Δ = 12-4·1·4
Δ = -15
Delta is less than zero, so there is no solution for the equation
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