m=4;(-1,1/2)

Solution for m=4;(-1,1/2) equation:

m=4(-1.1/2)

We move all terms to the left:

m-(4(-1.1/2))=0

We multiply all the terms by the denominator


m*2))-(4(-1.1=0

Wy multiply elements

2m^2-1.1=0

a = 2; b = 0; c = -1.1;
Δ = b2-4ac
Δ = 02-4·2·(-1.1)
Δ = 8.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{8.8}}{2*2}=\frac{0-\sqrt{8.8}}{4}
=-\frac{\sqrt{}}{4}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{8.8}}{2*2}=\frac{0+\sqrt{8.8}}{4}
=\frac{\sqrt{}}{4}
$