ma=-kx-FAcos(watA)

Simple and best practice solution for ma=-kx-FAcos(watA) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for ma=-kx-FAcos(watA) equation:


Simplifying
ma = -1kx + -1FAcos(watA)

Multiply cosAF * atwA
am = -1kx + -1acostwA2F

Reorder the terms:
am = -1acostwA2F + -1kx

Solving
am = -1acostwA2F + -1kx

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'acostwA2F' to each side of the equation.
acostwA2F + am = -1acostwA2F + acostwA2F + -1kx

Combine like terms: -1acostwA2F + acostwA2F = 0
acostwA2F + am = 0 + -1kx
acostwA2F + am = -1kx

Combine like terms: -1kx + kx = 0
acostwA2F + am + kx = 0

The solution to this equation could not be determined.

See similar equations:

| 3x=(320/4) | | 6.1y-302=26.08 | | 2-18=z/-8 | | (.8)^t=1/8 | | 0.4+0.2x=0.2+x | | 7z=14-35 | | -3.5=-.5g | | 96=r^2+10r | | 2(7c+5)= | | 2x+2.3=7.7 | | -9(9x+9)=10(10x+10) | | 3(2x+5)=2(6x-3) | | ln(x-23)-In(5-x)=In(4)+In(x) | | y^2+12y=35 | | 25=5(x-3) | | 2(x+3)+4(x-2)=0 | | -3.6h=(-10.8) | | 5lgx=3 | | 2x-3=-7x+12 | | 8/32 | | 1-4y=-32 | | 4n+8n+5n-3= | | 729^1/3 | | 14.4=(-2.4b) | | 4m=32/19 | | 2xsquerd+10x+13=0 | | 7x+3x-5+8x+5=180 | | 100=38(5x+2y) | | 3r^2+8r+4=0 | | ax^2-100=0 | | -2z+3+7=-12 | | X^2+y^2-7x+3y-5.75=0 |

Equations solver categories