mod(x+1)+mod(x-1)=3

Solution for mod(x+1)+mod(x-1)=3 equation:

Simplifying
mod(x + 1) + mod(x + -1) = 3

Reorder the terms:
dmo(1 + x) + mod(x + -1) = 3
(1 * dmo + x * dmo) + mod(x + -1) = 3
(1dmo + dmox) + mod(x + -1) = 3

Reorder the terms:
1dmo + dmox + dmo(-1 + x) = 3
1dmo + dmox + (-1 * dmo + x * dmo) = 3
1dmo + dmox + (-1dmo + dmox) = 3

Reorder the terms:
1dmo + -1dmo + dmox + dmox = 3

Combine like terms: 1dmo + -1dmo = 0
0 + dmox + dmox = 3
dmox + dmox = 3

Combine like terms: dmox + dmox = 2dmox
2dmox = 3

Solving
2dmox = 3

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '2mox'.
d = 1.5m-1o-1x-1

Simplifying
d = 1.5m-1o-1x-1