n(+4)=7(n+2)+4

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Solution for n(+4)=7(n+2)+4 equation: 



n(+4)=7(n+2)+4

We move all terms to the left:

n(+4)-(7(n+2)+4)=0

We add all the numbers together, and all the variables

n4-(7(n+2)+4)=0

We add all the numbers together, and all the variables

n^4-(7(n+2)+4)=0



We calculate terms in parentheses: -(7(n+2)+4), so:

7(n+2)+4

We multiply parentheses

7n+14+4

We add all the numbers together, and all the variables

7n+18

Back to the equation:

-(7n+18)



We do not support enpression: n^4

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