n(-3)-5=2(-n)-25

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Solution for n(-3)-5=2(-n)-25 equation: 



n(-3)-5=2(-n)-25

We move all terms to the left:

n(-3)-5-(2(-n)-25)=0

We add all the numbers together, and all the variables

n(-3)-(2(-1n)-25)-5=0

We multiply parentheses

-3n-(2(-1n)-25)-5=0



We calculate terms in parentheses: -(2(-1n)-25), so:

2(-1n)-25

We multiply parentheses

-2n-25

Back to the equation:

-(-2n-25)



We get rid of parentheses

-3n+2n+25-5=0

We add all the numbers together, and all the variables

-1n+20=0

We move all terms containing n to the left, all other terms to the right

-n=-20

n=-20/-1

n=+20

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