n(50)=46(n+3)-88

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Solution for n(50)=46(n+3)-88 equation: 



n(50)=46(n+3)-88

We move all terms to the left:

n(50)-(46(n+3)-88)=0

We add all the numbers together, and all the variables

n^50-(46(n+3)-88)=0



We calculate terms in parentheses: -(46(n+3)-88), so:

46(n+3)-88

We multiply parentheses

46n+138-88

We add all the numbers together, and all the variables

46n+50

Back to the equation:

-(46n+50)



We do not support enpression: n^50

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