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n(5n-9)=612
We move all terms to the left:
n(5n-9)-(612)=0
We multiply parentheses
5n^2-9n-612=0
a = 5; b = -9; c = -612;
Δ = b2-4ac
Δ = -92-4·5·(-612)
Δ = 12321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12321}=111$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-111}{2*5}=\frac{-102}{10} =-10+1/5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+111}{2*5}=\frac{120}{10} =12 $
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