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n(n+1)(n+2)(n+3)=3n*3n-6n
We move all terms to the left:
n(n+1)(n+2)(n+3)-(3n*3n-6n)=0
We add all the numbers together, and all the variables
n(n+1)(n+2)(n+3)-(-6n+3n*3n)=0
We get rid of parentheses
n(n+1)(n+2)(n+3)+6n-3n*3n=0
We multiply parentheses ..
n(+n^2+2n+n+2)(n+3)+6n-3n*3n=0
Wy multiply elements
n(+n^2+2n+n+2)(n+3)-9n^2+6n=0
We add all the numbers together, and all the variables
-9n^2+n(+n^2+2n+n+2)(n+3)+6n=0
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