n(n+1)(n+2)=504

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Solution for n(n+1)(n+2)=504 equation: 


Simplifying
n(n + 1)(n + 2) = 504

Reorder the terms:
n(1 + n)(n + 2) = 504

Reorder the terms:
n(1 + n)(2 + n) = 504

Multiply (1 + n) * (2 + n)
n(1(2 + n) + n(2 + n)) = 504
n((2 * 1 + n * 1) + n(2 + n)) = 504
n((2 + 1n) + n(2 + n)) = 504
n(2 + 1n + (2 * n + n * n)) = 504
n(2 + 1n + (2n + n2)) = 504

Combine like terms: 1n + 2n = 3n
n(2 + 3n + n2) = 504
(2 * n + 3n * n + n2 * n) = 504
(2n + 3n2 + n3) = 504

Solving
2n + 3n2 + n3 = 504

Solving for variable 'n'.

Reorder the terms:
-504 + 2n + 3n2 + n3 = 504 + -504

Combine like terms: 504 + -504 = 0
-504 + 2n + 3n2 + n3 = 0

The solution to this equation could not be determined.

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