n(n+1)+(n+2)=0

Solution for n(n+1)+(n+2)=0 equation:

Simplifying
n(n + 1) + (n + 2) = 0

Reorder the terms:
n(1 + n) + (n + 2) = 0
(1 * n + n * n) + (n + 2) = 0
(1n + n2) + (n + 2) = 0

Reorder the terms:
1n + n2 + (2 + n) = 0

Remove parenthesis around (2 + n)
1n + n2 + 2 + n = 0

Reorder the terms:
2 + 1n + n + n2 = 0

Combine like terms: 1n + n = 2n
2 + 2n + n2 = 0

Solving
2 + 2n + n2 = 0

Solving for variable 'n'.

Begin completing the square.

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + 2n + -2 + n2 = 0 + -2

Reorder the terms:
2 + -2 + 2n + n2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 2n + n2 = 0 + -2
2n + n2 = 0 + -2

Combine like terms: 0 + -2 = -2
2n + n2 = -2

The n term is 2n.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2n + 1 + n2 = -2 + 1

Reorder the terms:
1 + 2n + n2 = -2 + 1

Combine like terms: -2 + 1 = -1
1 + 2n + n2 = -1

Factor a perfect square on the left side:
(n + 1)(n + 1) = -1

Can't calculate square root of the right side.

The solution to this equation could not be determined.