n(n+1)-132=0

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Solution for n(n+1)-132=0 equation:


Simplifying
n(n + 1) + -132 = 0

Reorder the terms:
n(1 + n) + -132 = 0
(1 * n + n * n) + -132 = 0
(1n + n2) + -132 = 0

Reorder the terms:
-132 + 1n + n2 = 0

Solving
-132 + 1n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(-12 + -1n)(11 + -1n) = 0

Subproblem 1

Set the factor '(-12 + -1n)' equal to zero and attempt to solve: Simplifying -12 + -1n = 0 Solving -12 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -1n = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -1n = 0 + 12 -1n = 0 + 12 Combine like terms: 0 + 12 = 12 -1n = 12 Divide each side by '-1'. n = -12 Simplifying n = -12

Subproblem 2

Set the factor '(11 + -1n)' equal to zero and attempt to solve: Simplifying 11 + -1n = 0 Solving 11 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1n = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1n = 0 + -11 -1n = 0 + -11 Combine like terms: 0 + -11 = -11 -1n = -11 Divide each side by '-1'. n = 11 Simplifying n = 11

Solution

n = {-12, 11}

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