n(n+1)=-35

Solution for n(n+1)=-35 equation:

Simplifying
n(n + 1) = -35

Reorder the terms:
n(1 + n) = -35
(1 * n + n * n) = -35
(1n + n2) = -35

Solving
1n + n2 = -35

Solving for variable 'n'.

Reorder the terms:
35 + 1n + n2 = -35 + 35

Combine like terms: -35 + 35 = 0
35 + 1n + n2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-35' to each side of the equation.
35 + 1n + -35 + n2 = 0 + -35

Reorder the terms:
35 + -35 + 1n + n2 = 0 + -35

Combine like terms: 35 + -35 = 0
0 + 1n + n2 = 0 + -35
1n + n2 = 0 + -35

Combine like terms: 0 + -35 = -35
1n + n2 = -35

The n term is 1n.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
n + 0.25 + n2 = -35 + 0.25

Reorder the terms:
0.25 + n + n2 = -35 + 0.25

Combine like terms: -35 + 0.25 = -34.75
0.25 + n + n2 = -34.75

Factor a perfect square on the left side:
(n + 0.5)(n + 0.5) = -34.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.