n(n+2)=440

Solution for n(n+2)=440 equation:

Simplifying
n(n + 2) = 440

Reorder the terms:
n(2 + n) = 440
(2 * n + n * n) = 440
(2n + n2) = 440

Solving
2n + n2 = 440

Solving for variable 'n'.

Reorder the terms:
-440 + 2n + n2 = 440 + -440

Combine like terms: 440 + -440 = 0
-440 + 2n + n2 = 0

Factor a trinomial.
(-22 + -1n)(20 + -1n) = 0

Subproblem 1
Set the factor '(-22 + -1n)' equal to zero and attempt to solve:

Simplifying
-22 + -1n = 0

Solving
-22 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + -1n = 0 + 22

Combine like terms: -22 + 22 = 0
0 + -1n = 0 + 22
-1n = 0 + 22

Combine like terms: 0 + 22 = 22
-1n = 22

Divide each side by '-1'.
n = -22

Simplifying
n = -22
Subproblem 2
Set the factor '(20 + -1n)' equal to zero and attempt to solve:

Simplifying
20 + -1n = 0

Solving
20 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-20' to each side of the equation.
20 + -20 + -1n = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -1n = 0 + -20
-1n = 0 + -20

Combine like terms: 0 + -20 = -20
-1n = -20

Divide each side by '-1'.
n = 20

Simplifying
n = 20
Solution
n = {-22, 20}