n(n+2)=n+(n+2)+14

Solution for n(n+2)=n+(n+2)+14 equation:

Simplifying
n(n + 2) = n + (n + 2) + 14

Reorder the terms:
n(2 + n) = n + (n + 2) + 14
(2 * n + n * n) = n + (n + 2) + 14
(2n + n2) = n + (n + 2) + 14

Reorder the terms:
2n + n2 = n + (2 + n) + 14

Remove parenthesis around (2 + n)
2n + n2 = n + 2 + n + 14

Reorder the terms:
2n + n2 = 2 + 14 + n + n

Combine like terms: 2 + 14 = 16
2n + n2 = 16 + n + n

Combine like terms: n + n = 2n
2n + n2 = 16 + 2n

Add '-2n' to each side of the equation.
2n + -2n + n2 = 16 + 2n + -2n

Combine like terms: 2n + -2n = 0
0 + n2 = 16 + 2n + -2n
n2 = 16 + 2n + -2n

Combine like terms: 2n + -2n = 0
n2 = 16 + 0
n2 = 16

Solving
n2 = 16

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Simplifying
n2 = 16

Take the square root of each side:
n = {-4, 4}