n(n-1)(n+1)=-336

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Solution for n(n-1)(n+1)=-336 equation: 



n(n-1)(n+1)=-336

We move all terms to the left:

n(n-1)(n+1)-(-336)=0

We add all the numbers together, and all the variables

n(n-1)(n+1)+336=0

We use the square of the difference formula

n^2-1+336=0

We add all the numbers together, and all the variables

n^2+335=0

a = 1; b = 0; c = +335;
Δ = b2-4ac
Δ = 02-4·1·335
Δ = -1340
Delta is less than zero, so there is no solution for the equation

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