n(n-1)(n+1)=120

Solution for n(n-1)(n+1)=120 equation:

Simplifying
n(n + -1)(n + 1) = 120

Reorder the terms:
n(-1 + n)(n + 1) = 120

Reorder the terms:
n(-1 + n)(1 + n) = 120

Multiply (-1 + n) * (1 + n)
n(-1(1 + n) + n(1 + n)) = 120
n((1 * -1 + n * -1) + n(1 + n)) = 120
n((-1 + -1n) + n(1 + n)) = 120
n(-1 + -1n + (1 * n + n * n)) = 120
n(-1 + -1n + (1n + n2)) = 120

Combine like terms: -1n + 1n = 0
n(-1 + 0 + n2) = 120
n(-1 + n2) = 120
(-1 * n + n2 * n) = 120
(-1n + n3) = 120

Solving
-1n + n3 = 120

Solving for variable 'n'.

Reorder the terms:
-120 + -1n + n3 = 120 + -120

Combine like terms: 120 + -120 = 0
-120 + -1n + n3 = 0

The solution to this equation could not be determined.