n(n-1)(n-2)(n-3)(n-4)(n-5)+0=0

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Solution for n(n-1)(n-2)(n-3)(n-4)(n-5)+0=0 equation: 



n(n-1)(n-2)(n-3)(n-4)(n-5)+0=0

We add all the numbers together, and all the variables

n(n-1)(n-2)(n-3)(n-4)(n-5)=0

We multiply parentheses ..

n(+n^2-2n-1n+2)(n-3)(n-4)(n-5)=0

We multiply parentheses ..

n(+n^2-2n-1n+2)(+n^2-4n-3n+12)(n-5)=0

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