n(n-1)(n-2)(n-3)(n-4)(n-5)/720=28

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Solution for n(n-1)(n-2)(n-3)(n-4)(n-5)/720=28 equation: 



n(n-1)(n-2)(n-3)(n-4)(n-5)/720=28

We move all terms to the left:

n(n-1)(n-2)(n-3)(n-4)(n-5)/720-(28)=0

We multiply parentheses ..

n(+n^2-2n-1n+2)(n-3)(n-4)(n-5)/720-28=0

We multiply all the terms by the denominator


n(+n^2-2n-1n+2)(n-3)(n-4)(n-5)-28*720=0

We add all the numbers together, and all the variables

n(+n^2-2n-1n+2)(n-3)(n-4)(n-5)-20160=0

We multiply parentheses ..

n(+n^2-2n-1n+2)(+n^2-4n-3n+12)(n-5)-20160=0

We move all terms containing n to the left, all other terms to the right

n(+n^2-2n-1n+2)(+n^2-4n-3n+12)(n-5)=20160

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