n(n-1)(n-2)(n-3)(n-4)(n-5)=210

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Solution for n(n-1)(n-2)(n-3)(n-4)(n-5)=210 equation:



n(n-1)(n-2)(n-3)(n-4)(n-5)=210
We move all terms to the left:
n(n-1)(n-2)(n-3)(n-4)(n-5)-(210)=0
We multiply parentheses ..
n(+n^2-2n-1n+2)(n-3)(n-4)(n-5)-210=0
We multiply parentheses ..
n(+n^2-2n-1n+2)(+n^2-4n-3n+12)(n-5)-210=0
We move all terms containing n to the left, all other terms to the right
n(+n^2-2n-1n+2)(+n^2-4n-3n+12)(n-5)=210

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