n(n-1)(n-2)(n-3)(n-4)=2520

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Solution for n(n-1)(n-2)(n-3)(n-4)=2520 equation:



n(n-1)(n-2)(n-3)(n-4)=2520
We move all terms to the left:
n(n-1)(n-2)(n-3)(n-4)-(2520)=0
We multiply parentheses ..
n(+n^2-2n-1n+2)(n-3)(n-4)-2520=0
We multiply parentheses ..
n(+n^2-2n-1n+2)(+n^2-4n-3n+12)-2520=0
We move all terms containing n to the left, all other terms to the right
n(+n^2-2n-1n+2)(+n^2-4n-3n+12)=2520

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