n(n-1)(n-2)+n(n-1)=28n

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Solution for n(n-1)(n-2)+n(n-1)=28n equation: 



n(n-1)(n-2)+n(n-1)=28n

We move all terms to the left:

n(n-1)(n-2)+n(n-1)-(28n)=0

We add all the numbers together, and all the variables

-28n+n(n-1)(n-2)+n(n-1)=0

We multiply parentheses

n^2-28n+n(n-1)(n-2)-1n=0

We multiply parentheses ..

n^2+n(+n^2-2n-1n+2)-28n-1n=0

We add all the numbers together, and all the variables

n^2+n(+n^2-2n-1n+2)-29n=0

We multiply parentheses

n^2+n^3-2n^2-1n^2+2n-29n=0

We do not support enpression: n^3

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