n(n-1)(n-2)=120

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Solution for n(n-1)(n-2)=120 equation: 


Simplifying
n(n + -1)(n + -2) = 120

Reorder the terms:
n(-1 + n)(n + -2) = 120

Reorder the terms:
n(-1 + n)(-2 + n) = 120

Multiply (-1 + n) * (-2 + n)
n(-1(-2 + n) + n(-2 + n)) = 120
n((-2 * -1 + n * -1) + n(-2 + n)) = 120
n((2 + -1n) + n(-2 + n)) = 120
n(2 + -1n + (-2 * n + n * n)) = 120
n(2 + -1n + (-2n + n2)) = 120

Combine like terms: -1n + -2n = -3n
n(2 + -3n + n2) = 120
(2 * n + -3n * n + n2 * n) = 120
(2n + -3n2 + n3) = 120

Solving
2n + -3n2 + n3 = 120

Solving for variable 'n'.

Reorder the terms:
-120 + 2n + -3n2 + n3 = 120 + -120

Combine like terms: 120 + -120 = 0
-120 + 2n + -3n2 + n3 = 0

The solution to this equation could not be determined.

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