n(n-2)/3=78

Solution for n(n-2)/3=78 equation:

n(n-2)/3=78

We move all terms to the left:

n(n-2)/3-(78)=0

We multiply all the terms by the denominator


n(n-2)-78*3=0

We add all the numbers together, and all the variables

n(n-2)-234=0

We multiply parentheses

n^2-2n-234=0

a = 1; b = -2; c = -234;
Δ = b2-4ac
Δ = -22-4·1·(-234)
Δ = 940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{940}=\sqrt{4*235}=\sqrt{4}*\sqrt{235}=2\sqrt{235}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{235}}{2*1}=\frac{2-2\sqrt{235}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{235}}{2*1}=\frac{2+2\sqrt{235}}{2}
$