n(n-3)=1120

Solution for n(n-3)=1120 equation:

Simplifying
n(n + -3) = 1120

Reorder the terms:
n(-3 + n) = 1120
(-3 * n + n * n) = 1120
(-3n + n2) = 1120

Solving
-3n + n2 = 1120

Solving for variable 'n'.

Reorder the terms:
-1120 + -3n + n2 = 1120 + -1120

Combine like terms: 1120 + -1120 = 0
-1120 + -3n + n2 = 0

Factor a trinomial.
(-32 + -1n)(35 + -1n) = 0

Subproblem 1
Set the factor '(-32 + -1n)' equal to zero and attempt to solve:

Simplifying
-32 + -1n = 0

Solving
-32 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + -1n = 0 + 32

Combine like terms: -32 + 32 = 0
0 + -1n = 0 + 32
-1n = 0 + 32

Combine like terms: 0 + 32 = 32
-1n = 32

Divide each side by '-1'.
n = -32

Simplifying
n = -32
Subproblem 2
Set the factor '(35 + -1n)' equal to zero and attempt to solve:

Simplifying
35 + -1n = 0

Solving
35 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-35' to each side of the equation.
35 + -35 + -1n = 0 + -35

Combine like terms: 35 + -35 = 0
0 + -1n = 0 + -35
-1n = 0 + -35

Combine like terms: 0 + -35 = -35
-1n = -35

Divide each side by '-1'.
n = 35

Simplifying
n = 35
Solution
n = {-32, 35}